Iridium SPDF Electron Configuration Explained
Iridium has atomic number 77, meaning it has 77 electrons to arrange across its orbitals. Its ground-state electron configuration is:
Full notation: `1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰ 5s² 5p⁶ 4f¹⁴ 5d⁷ 6s²`
Shorthand notation: `[Xe] 4f¹⁴ 5d⁷ 6s²`
This configuration places Iridium in the D-block of the periodic table — Period 6, Group 9. The last subshell filled (the d subshell) determines its block.
SPDF notation tells you exactly: which subshell each electron occupies, how many electrons are in it, and the energy level of each group. This is far more detail than the simpler Bohr model, which only shows shell totals.
Aufbau Filling Sequence for Iridium
The Aufbau (building-up) principle states electrons fill the lowest available energy subshell first. For Iridium (Z=77), the filling stops at the 6s² subshell.
Standard Aufbau sequence:
1s → 2s → 2p → 3s → 3p → 4s → 3d → 4p → 5s → 4d → 5p → 6s → 4f → 5d → 6p → 7s → 5f → 6d → 7p
After filling, Iridium's configuration ends at 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰ 5s² 5p⁶ 4f¹⁴ 5d⁷ 6s², with 9 valence electrons in its outermost subshell. Note: Iridium is a D-block element, so watch for possible Aufbau anomalies driven by extra stability of half-filled or fully-filled d subshells.
Orbital Diagram of Iridium (s, p, d, f)
The orbital diagram of Iridium expands the configuration 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰ 5s² 5p⁶ 4f¹⁴ 5d⁷ 6s² into individual orbital boxes:
- Each s subshell holds max 2 electrons (1 orbital)
- Each p subshell holds max 6 electrons (3 orbitals)
- Each d subshell holds max 10 electrons (5 orbitals)
- Each f subshell holds max 14 electrons (7 orbitals)
Hund's Rule dictates that within any subshell, electrons fill each orbital singly (spin up ↑) before pairing. This avoids electron–electron repulsion. Iridium's D-block placement confirms its last orbitals are d type.
The interactive diagram above shows Iridium's complete subshell breakdown with orbital boxes for every energy level.
How to Write Iridium's Electron Configuration
Follow these steps to write Iridium's electron configuration from scratch:
Step 1: Identify the atomic number: Z = 77 — this is the total number of electrons to place.
Step 2: Follow the Aufbau sequence, filling the lowest energy subshells first:
> 1s → 2s → 2p → 3s → 3p → 4s → 3d → 4p → ...
Step 3: Apply Hund's Rule inside each subshell — one electron per orbital before pairing begins.
Step 4: Apply the Pauli Exclusion Principle — each orbital holds at most 2 electrons with opposite spins.
Step 5: After filling all 77 electrons, your result should match:
> 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰ 5s² 5p⁶ 4f¹⁴ 5d⁷ 6s²
Shorthand: Replace the preceding noble gas core with its symbol:
> [Xe] 4f¹⁴ 5d⁷ 6s²
⚠️ Common mistake: Iridium is a d-block element. Verify your d-subshell count carefully — anomalies from expected Aufbau order are possible.
Why Iridium Matters (Real-World Insight)
🔬 Element Comparison
Iridium vs Platinum — Key Differences
Although Iridium (Z=77) and Platinum (Z=78) are adjacent on the periodic table, they behave very differently. Iridium has 9 valence electrons vs Platinum's 10. Their electronegativity gap is 0.08 — a critical factor in predicting bond polarity when the two interact.
Valence Electrons & D-Block Position
Iridium has 9 valence electrons — the electrons in its highest occupied principal energy level.
As a D-block element, Iridium's valence electrons reside in d orbitals and d/f orbitals. These are the only electrons involved in chemical bonding.
| Block | Type | Max Valence e⁻ |
|---|---|---|
| s-block | Groups 1–2 | 1–2 |
| p-block | Groups 13–18 | 3–8 |
| d-block | Groups 3–12 | up to 10 |
| f-block | Lanthanides/Actinides | up to 14 |
Iridium sits in this table as a d-block element with 9 valence electrons.
→ See Iridium's valence electrons in the Bohr model for the shell-based view.
→ Electronegativity of Iridium — how strongly it attracts these electrons.
Frequently Asked Questions
Q. How many electrons does Iridium have?
Iridium has 77 electrons, matching its atomic number. In a neutral atom, these are balanced by 77 protons in the nucleus.
Q. What is the shell structure of Iridium?
The electron shell distribution for Iridium is 2, 8, 18, 32, 15, 2. This shows how all 77 electrons are arranged across 6 principal energy levels.
Q. How many valence electrons does Iridium have?
Iridium has 9 valence electrons in its outermost shell. These are responsible for its chemical bonding and placement in Group 9.
Q. What is the SPDF configuration of Iridium?
The full configuration is 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰ 5s² 5p⁶ 4f¹⁴ 5d⁷ 6s². This describes the exact subshell occupancy following the Aufbau principle.
Q. What block is Iridium in?
Iridium is in the D-block because its highest-energy electrons occupy d orbitals.

